Study on the flyISEE UpperMathematics AchievementSolid geometry (surface area, volume)

Mathematics Achievement

Solid geometry (surface area, volume) — ISEE Upper practice questions

  • 47 questions on the paper
  • 95 practice questions in the app
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What this topic is

Solid geometry (surface area, volume) on the ISEE Upper Mathematics Achievement test covers finding the surface area and volume of three-dimensional figures such as rectangular boxes, spheres, and cones.

A student must choose the correct formula, substitute given dimensions, and solve for a missing measure such as a radius when area or volume is known. Items usually appear as short word problems about everyday objects, and the needed formula is sometimes printed in the stem.

Answer choices are typically lengths, areas, or volumes, often written with π. Common traps include mixing surface area with volume, omitting a face of a closed solid, or treating a diameter as a radius.

Sample questions

Pick an answer to see whether it is right — nothing is saved, and nothing needs an account.

Question 1Easier

A closed rectangular box measures 6 cm by 5 cm by 4 cm. What is the total surface area of the box?

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Answer: C — 148 cm2148\text{ cm}^2

Surface area is 2(65+64+54)=2(30+24+20)=1482(6\cdot5 + 6\cdot4 + 5\cdot4) = 2(30 + 24 + 20) = 148. Omitting the factor of 2 or computing volume 654=1206\cdot5\cdot4 = 120 yields common distractors.

Question 2Mid

A spherical ornament has surface area 100π100\pi square centimeters. What is the radius of the ornament?

(SA=4πr2)(SA=4\pi r^{2})
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Answer: B — 5 cm

4πr2=100π4\pi r^{2}=100\pir2=25r^{2}=25r=5r=5.

Question 3Mid

An ice-cream cone has volume 48π48\pi cubic centimeters and height 9 centimeters. What is the radius of its circular base?

(V=13πr2h)(V=\dfrac{1}{3}\pi r^{2}h)
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Answer: D — 4 cm

48π=13πr2(9)48\pi=\dfrac{1}{3}\pi r^{2}(9)48=3r248=3r^{2}r2=16r^{2}=16r=4r=4.

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Practice 95 Solid geometry (surface area, volume) questions in the app

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